- Merupakan satu rangkaian organisasi yg dibahagikan kepada subnetwork yg mna membenarkan sambungan ke internet dgn satu share network address
- Merujuk kepada network yg besar
- Group dan segment merupakan network
- Tujuannya supaya network senang utk di kawal
- Dari satu group besar yg di pecahkan menjadi group2 kecil
- Apabila menggunakan subnetting ia blh mengurangkan data collusion(pelanggaran data)
Sebelum subnet
- Brodcast tinggi, data collusion tinggi, network performance rendah
Selepas subnet
- Brodcast rendah, data collusion rendah, network performance tinggi
p/s - bila komunikasi tidak berfungsi, periksa IP
=============================================
Latihan
8bit | 16bit | 24bit | 32bit |
192 | 168 | 3 | 0 |
*1 obtec mempunyai 8 bit = 0000 0000
Guna 10 network
2 ^ n brapa dapat 10
2 ^ 4 = 16(lebin xpa)
*16 PC yg boleh masuk network
Bila n = 4, so 0000 0000 akan jadi 1111 0000
Jadi 24bit + 4 = 28 (Subnet)
Jawapan = 192.168.3.0/28
============================================
2 ^ n utk cari subnet
n = bil. bit 1
2 ^ x utk cari host
x = bil. bit 0
============================================
Latihan
192.168.5.0/xx (kelas C)
7 segment/group/network
- cari nilai xx
- bil. host
nilai xx
2 ^ n = 7
2 ^ 3 = 8 0000 0000 -> 1110 0000
24 + 3 = 27 (subnet)
Jawapan = 192.168.5.0/27
bil. host
2 ^ x = bil. host (bil. bit kosong)
2 ^ 5 = 32 host tolak 2 (Brodcast & Network Address)
= 30 host (PC y blh masuk network)
192.168.5.0/27 (kelas C)
bil.host = 32, bil.subnet = 8
Network Address | Range | Broadcast Address |
0 | 1 - 30 | 31 |
32 | 32 - 62 | 63 |
64 | 65 - 94 | 95 |
96 | 97 - 126 | 127 |
128 | 129 - 158 | 159 |
160 | 161 - 190 | 191 |
192 | 193 - 222 | 223 |
contoh IP
Network Address : 192.168.5.0/32/64/96
Brodcast Address : 192.168.5.31/63/96
Host : 192.168.5.1-30/32-62/65-94
nk cari 223(BOLD)
Network Address(NA)
= bil.host x (segment - 1)
= 32 x (7 - 1)
= 192
Brodcast Address(BA)
99.10.70.3/10 (kelas A)
10 = 1111 1111.1100 0000.0000 0000.0000 0000
2 ^ x = bil. bit '0'
Network Address | Range | Brodcast Address |
0 | 1 - 62 | 63 |
64 | 65 - 126 | 127 |
128 | 129 - 190 | 191 |
192 | 193 - 254 | 255 |
============================================
Task
4 server, 2 printer, 200 PC, 2 dept.(IT & Elec.)
Server 1
Server 3
Server 4
S3 & S4 mnggunakan 1 printer yg sama
*utk Electrical Department
rujukan : http://en.wikipedia.org/wiki/Subnetting
Hi, I came across your site and wasn’t able to get an email address to contact you about some broken links on your site. Please email me back and I would be happy to point them out to you.
ReplyDeleteThanks!
Frank
frank641w@gmail.com